Matematika

Pertanyaan

jika tan A = 4/3 dan A lancip maka nilai sin A + cos A =..?

2 Jawaban

  • tanA = 4/3 → y= 4 dan x = 3
    r = √(x² + y²) = √(3² + 4²) = 5
    sinA + cosA = y/r + x/r
    = 4/5 + 3/5 
    = 7/5
  • Tan A = Desa (depan/samping) (Gambar segitiga siku)
    Tan A = 4/3
    cari sisi miring
    Sisi miring = √Depan^2 + Samping ^2
    = √4^2 + 3 ^2
    = √16 + 9
    = √25
    = 5
    Sin A = Demi (depan/miring)
    = 4/5
    Cos A = Sami (samping/miring)
    = 3/5
    Sin A + Cos A = 4/5 + 3/5
    = 7/5

Pertanyaan Lainnya