Matematika

Pertanyaan

f(x)=x²-3xdan g(x)=f(x²-2)-2f(-1) maka fungsi dari g(x) adalah...

2 Jawaban

  • f(x) = x² - 3x

    g(x) = f(x² - 2) - 2f(-1)
    = ((x² - 2)² - 3(x² - 2)) - 2((-1)² - 3(-1))
    = (x⁴ - 4x² + 4) - (3x² - 2) - 2(1 - (-3))
    = x⁴ - 4x² + 4 - 3x² + 2 - 2(1 + 3)
    = x⁴ - 7x² + 6 - 2(4)
    = x⁴ - 7x² + 6 - 8
    = x⁴ - 7x² - 2
  • f(x) = x^2 - 3x ====> f(-1) = (-1)^2 - 3(-1) = 1 + 3 = 4
    f(x^2 - 2) = (x^2 - 2)^2 - 3(x^2 - 2)
    f(x^2 - 2) = x^4 - 4x^2 + 4 - 3x^2 + 6
    f(x^2 - 2) = x^4 - 7x^2 + 10

    g(x) = f(x^2 - 2) - 2f(-1)
    = x^4 - 7x^2 + 10 - 2(4)
    = x^4 - 7x^2 + 2

    ^ = pangkat

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