tolong di jawab soal ini ya kk(please)

(f o g)(x) = f(g(x))
1/x-2 √x² - 4x + 5 = √g(x)² + 1
[1/x-2 √x² - 4x + 5]² = g(x)² + 1
1/(x-2)² x² - 4x + 5 = g(x)² + 1
x² - 4x + 5 / x² -4x + 4 = g(x)² + 1
[x² - 4x + 5 / x² -4x + 4] - 1 = g(x)²
[x² - 4x + 5 / x² -4x + 4] - [ x² -4x + 4 / x² -4x + 4 ] = g(x)²
[x² - 4x + 5 - (x² -4x + 4)] / x² -4x + 4 = g(x)²
[1/x² -4x + 4] = g(x)²
[1/(x-2)²] = g(x)²
1/x-2 = g(x)
g(3-x) = 1/(3-x) - x
= 1/ 3-2x
Sorry ya kalo salah....