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Pertanyaan

diketahui x1 dan x2 adalah akar akar persamaan kuadrat x2+6x+2=0 ,maka
X1^2-X2^2)^2 +X1^2+X2^2

1 Jawaban

  • x^2 + 6x + 2 = 0
    x1 + x2 = -b/a = -6/1 = -6
    x1.x2 = c/a = 2/1 = 2
    x1 - x2 = √D/a = √(b^2 - 4ac) / a = √(6^2 - 4(1)(2)) / 1 = √(36 - 8) = √28

    (x1^2 - x2^2)^2 + x1^2 + x2^2
    = ((x1 + x2)(x1 - x2))^2 + (x1 + x2)^2 - 2x1x2
    = ((-6)(√28))^2 + (-6)^2 - 2(2)
    = 36(28) + 36 - 4
    = 1.008 + 32
    = 1.040

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