122°F=......°C 68°C=........°F
Fisika
Sandyyii
Pertanyaan
122°F=......°C
68°C=........°F
68°C=........°F
2 Jawaban
-
1. Jawaban MonFlica
1) 5/9 × (122-32)
5/9 × 90
= 50°C
2) 9/5 × (68+32)
9/5 × 120
=216°F -
2. Jawaban yusak041
122°F = °C
122°F = 5/9 × (t-32)°C
122°F = 5/9 × (122-32)°C
122°F = 5/9 × 90°C
122°F = 5 × 10°C
122°F = 50°C
68°C = °F
68°C = 9/5 × (t + 32)°F
68°C = 9/5 × (68 + 32)°F
68°C = 9/5 × 100
68°C = 9 × 20
68°C = 180°F