Diketahui sebuah rumus f= ax+b. Jika f (-2)= 14 dan f (3) = -1. Maka tentukan f(7)+f(10)=.......

f(x) = ax + b
f(-2) = 14
f(3) = -1

Eliminasi
-2a + b = 14
3a + b = -1
_________-
-5a = 15
a = 15/-5
a = -3

Substitusi
-2a + b = 14
-2(-3) + b = 14
6 + b = 14
b = 14 - 6
b = 8

f(7) = 7a + b
=> 7(-3) + 8
=> -21 + 8
=> -13

f(10) = 10a + b
=> 10(-3) + 8
=> -30 + 8
=> -22

f(7) + f(10) = (-13) + (-22) = -35