Mohon bantuannya untuk nomor 2, 4, dan 6. Pakai cara, tolong. :'((

Integral substitusi

2) Jwab A
= ∫(3x-1)(3x² -2x+7)⁻⁷ dx =
= (3x-1)/(6x -2) . (-1/6) ( 1/ (3x² -2x +7)⁶ +c
= - (3x-1) / {2(3x-1)(6)(3x² -2x+ 7)⁶ +x
= -1/ { 12 (3x² -2x +7)⁶} + c

4) B
= ∫ (3x-2)(3x²-4x)¹/²  dx
= (3x-2)/ (6x-4)  . (2/3). (3x² -4x)³/²
= (3x-2)/ 2(3x-2) . (2/3) (3x²-4x)√(3x² -4x)
= 1/2 . 2/3. (3x²-4x)√(3x²-4x)
= 1/3 (3x² -4x) √(3x² -4x) + C

6. Jwab A
∫√(t⁴ -3t²) dt = ∫{ t²(t²-3)}
= ∫ t√(t²-3) dt
=  ∫ t (t²-3)¹/² dt
=  ( t/ 2t) .(2/3) (t²-3)³/² + c
= (1/2)(2/3) (t²-3)√(t²-3) + C
= 1/3 (t²-3) √(t²-3) + C