Bantu jawab guys pakai cara ya untuk no 10

Lim √x² + 3 - x - 1 / 1 - x²
x→1

Lim √x² + 3 - (x + 1) / 1 - x²
x→1

Lim √x² + 3 - (x + 1) (√x² + 3 + (x + 1)
x→1 .. / (1 - x²)(√x² + 3 + (x + 1)

Lim x² + 3 - (x + 1)²
x→1 .. / (1 - x²)(√x² + 3 + (x + 1)

Lim x² + 3 - (x² + 2x + 1)
x→1 .. / (1 - x²)(√x² + 3 + (x + 1)

Lim x² - x² - 2x + 3 - 1
x→1 .. / (1 - x²)(√x² + 3 + (x + 1)

Lim -2x + 2 / (1 - x²)(√x² + 3 + (x + 1)
x→1

Lim 2 (1 - x)
x→1 .. / (1 - x)(1 + x)(√x² + 3 + (x + 1)

Lim 2 / (1 + x)(√x² + 3 + (x + )
x→1

= 2 / (1 + 1)(√1² + 3 + (1 + 1)

= 2 / √4 + 2

= 2 / 2 + 2

= 2/4

= 1/2