Bantu jawab no.9 guys pakai cara ya

2/2x ×1/√2x+3 (diturunkan)
=2/6 × 1/√9 (dimasukkan)
=2/6×3
=2/18
=1/9

Lim x - √2x + 3 / x² - 9
x→3

Lim x - √2x + 3 (x + √2x + 3)
x→3 .. / (x² - 9)(x + √2x + 3)

Lim x² - (2x + 3)
x→3 .. / (x² - 9)(x + √2x + 3)

Lim x² - 2x - 3
x→3 .. / (x² - 9)(x + √2x + 3)

Lim (x - 3)(x + 1)
x→3 .. / (x - 3)(x + 3)(x + √2x + 3)

Lim (x + 1) / (x + 3)(x + √2x + 3)
x→3

= 3 + 1 / (3 + 3)(3 + √2(3) + 3)

= 4 / 6 (3 + √9)

= 2 / 3 (3 + 3)

= 2 / 3 (6)

= 1 / 3 (3)

= 1/9