Bantu Jawab soal no.20 pakai Penyelesaian ya

Lim √x - √2x - 1 / x - 1
x→1

Lim √x - √2x - 1 (√x + √2x - 1)
x→1 . . . . / x - 1 (√x + √2x - 1)

Lim x - (2x - 1) / x - 1 (√x + √2x - 1)
x→1

Lim -x + 1 / x - 1 (√x + √2x - 1)
x→1

Lim - (x - 1) / (x - 1)(√x + √2x - 1)
x→1

Lim -1 / √x + √2x - 1
x→1

= -1 / √1 + √2(1) - 1

= -1 / 1 + √2 - 1

= -1 / 1 + 1

= -1/2