Jika fungsi f(x)=x+2a-b dan g(x) = 2bx+2. Serta 4f(0) = 3g(1), maka 4a-5b =

4f(0) = 3g(1)
4(0 + 2a -b) = 3(2b + 2)
4(2a - b) = 3(2b + 2)
8a - 4b = 6b + 6
8a - 4b - 6b = 6
8a - 10b = 6
------------------ (bagi 2)
4a - 5b = 3

f(x) = x + 2a - b => f(0) = 0 + 2a - b = 2a - b
g(x) = 2bx + 2 => g(1) = 2b(1) + 2 = 2b + 2
4f(0) = 3g(1)
4(2a - b) = 3(2b + 2)
8a - 4b = 6b + 6
8a - 10b = 6 ....... (bagi 2)
4a - 5b = 3