(sin60°cos45°-cos60°sin45°)²???
Matematika
arwu
Pertanyaan
(sin60°cos45°-cos60°sin45°)²???
1 Jawaban
-
1. Jawaban GayuhTR
(sin60°cos45°-cos60°sin45°)²=
(√3/2*√2/2-1/2*√2/2)²=
(√6/4-√2/4)²=
(√6-√2)²/16=
(6-2√12+2)/16=
{8-2√(4.3)}/16=
(8-4√3)/16=
4(2-√3)/16=
(2-√3)/4