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Pertanyaan

Persamaan garis melalui (3,1) dan (-2,2)

1 Jawaban

  • x1 = 3
    x2 = -2

    y1 = 1
    y2 = 2

    rumus :
    (y-y1)/(y2-y1) = (x-x1)/(x2-x1)
    (y-1)/(2-1) = (x-3)/(-2-3)
    (y-1)/1 = (x-3)/-5
    -5(y-1) = 1(x-3)
    -5y +5 = x -3
    -x -5y +5+3 = 0
    x + 5y -8 = 0

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