Matematika

Pertanyaan

materi sinus co sinus bantuin saya ya
materi sinus co sinus bantuin saya ya

2 Jawaban

  • Begitulah jawaban saya
    Gambar lampiran jawaban Trishafayola
  • aturan sinus

    [tex] \frac{a}{sin A}= \frac{b}{sin B} \\ \frac{4 \sqrt{6} }{sin 60}= \frac{8}{sin B} \\ \frac{4 \sqrt{6} }{ \frac{1}{2} \sqrt{3} }= \frac{8}{sin B} \\ 4 \sqrt{6}sin B=4 \sqrt{3} \\ sinB= \frac{4 \sqrt{3} }{ 4\sqrt{6} } \\ sinB=\frac{4 \sqrt{3} }{ 4\sqrt{6} }. \frac{ \sqrt{6} }{ \sqrt{6} } \\ sinB= \frac{ 4\sqrt{18} }{24} \\ sinB=\frac{ 4.3\sqrt{2} }{24} \\ sinB=\frac{ 12\sqrt{2} }{24} \\ sinB = \frac{ 1 }{2} \sqrt{2} \\ B=45 ^{o} \\ C=180 ^{o}-(45^{o}+60 ^{o}) \\ C=75 ^{o}[/tex]