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Pertanyaan

Berapa ph campuran yg terjadi bila 200 ml larutan HCOOH 0,1 mol ka10-5 dicampur Dengan 20 ml larutan HCOONa 1 mol

1 Jawaban

  • dik : 200ml HCOOH 0,1 mol
    ka = 10^-5
    20 ml HCOONa 1 mol
    dit : pH campuran
    jawab :
    HCOOH = 200×0,1 = 20mmol
    HCOONa = 20×1 = 20 mmol
    [H+] = Ka×Al/garam
    [H+] = 10^-5×20/20
    [H+] = 10^-5
    pH = 5

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