Matematika

Pertanyaan

1) Lim x=3 x-3/x2-5x+6 2) lim x=1 2(x+3)2/x2+8x+15

1 Jawaban

  • Langsung aja y

    1.
    lim (x-3) / (x²-5x+6)
    x→3

    lim (x-3) / (x-3)(x-2)
    x→3

    = 1 / 3-2
    = 1/1
    = 1

    2.
    lim 2(x+3)² / x²+8x+15
    x→1

    lim 2(x+3)(x+3) / (x+3)(x+5)
    x→1

    lim 2(x+3) / (x+5)
    x→1

    = 2(1+3) / (1+5)
    = 8/6
    = 4/3

    semoga berguna +_+

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