dibantu dong no.1 yaaa
Matematika
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Pertanyaan
dibantu dong no.1 yaaa
1 Jawaban
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1. Jawaban rawgni
sin(B)/AO = sin(A)/BO
sin(30)/AO = sin(45)/6
AO = 6sin(30)/sin(45)
AO = 6*(1/2)/(1/2 √2)
AO = 6/√2
AJ² = JO²+AO² - 2(JO)(AO) cos O
AJ² = (6√2)² + (6/√2)² - 2 (6√2) (6/√2) cos(60)
AJ² = 72 + 18 - 72cos(60)
AJ² = 90 - 72/2
AJ² = 90 - 36
AJ² = 54
AJ = √54
AJ = √(9 * 6)
AJ = 3√6