Matematika

Pertanyaan

dibantu dong no.1 yaaa
dibantu dong no.1 yaaa

1 Jawaban

  • sin(B)/AO = sin(A)/BO
    sin(30)/AO = sin(45)/6
    AO = 6sin(30)/sin(45)
    AO = 6*(1/2)/(1/2 √2)
    AO = 6/√2

    AJ² = JO²+AO² - 2(JO)(AO) cos O
    AJ² = (6√2)² + (6/√2)² - 2 (6√2) (6/√2) cos(60)
    AJ² = 72 + 18 - 72cos(60)
    AJ² = 90 - 72/2
    AJ² = 90 - 36
    AJ² = 54
    AJ = √54
    AJ = √(9 * 6)
    AJ = 3√6