larutan jenuh B(OH)3 memiliki PH 9, maka Ksp B(OH)3 adalah

pOH = 5
pOH = - log OH-
5 = - log OH-

OH- = 10^-5
OH- = v.basa x Mb
10^-5 = 3 x Mb
Mb = 1/3 x 10^-5

B(OH)3 ==> B3+ + 3OH-
Ksp = s^3 x 3s
Ksp = 3s^4
Ksp = 3 x (1/3x10^-5)^4
Ksp = 1/27 x 10^-20