diketahui sin A=3/5 dan cos B=5/13 .hitunglah nilai :sin A.cos B+CosA.Sin B

sinA = 3/5 ← y = 3 dan r = 5
x = √(r² - y²) = 4
cosA = x/r = 4/5
cosB = 5/13, x = 5 dan r = 13
y = √(r² - x²) = 12
sinB = y/r = 12/13
sinA cosB + cosA sinB = (3/5)(5/13) + (4/5)(12/13)
= 63/65