jika f(x) = x²- 2x + 3 maka titi minimum dari f(x-1) adalah

f(x) = x² - 2x + 3
f(x - 1) = (x - 1)² - 2(x - 1) + 3
= x² - 2x + 1 - 2x + 2 + 3
= x² - 4x + 6
f'(x - 1) = 2x - 4 = 0
2x = 4
x = 2

f(2 - 1) = f(1)
f(1) = 1² - 2(1) + 3
= 1 - 2 + 3
= 2

(2, 2)