Suatu fungsi dirumuskan dengan f(x)=px+q.Jika f(-2)=14 dan f(3)=-1 , nila p dan q berturut turut adalah a. -3 & 8 b. -3 & -8 c. 3 & 8 b. 3 &-8

f(x) = px + q
f(-2) = 14
f(3) = -1

f(-2) = p(-2) + q = 14
f(3) = p(3) + q = -1

eliminasi
-2p + q = 14
3p + q = -1
---------------- -
-5p = 15
p = -3
u/ q = 3(-3) + q = -1
-9 + q = -1
q = 8

jawabannya A

f(x) = px + q
f(-2) = 14
f(3) = -1

Eliminasi
f(-2) = -2p + q = 14
f(3) = 3p + q = -1
______________-
-5p = 15
p = 15/-5
p = -3

Substitusi
-2p + q = 14
-2(-3) + q = 14
-6 + q = 14
q = 14 - 6
q = 8

Nilai p = -3 dan nilai q = 8
Jawabannya A