Matematika

Pertanyaan

kakpoinyya 26 tolong no 2 sampe 5
kakpoinyya  26 tolong no 2 sampe 5

1 Jawaban

  • 2) a = (1 , 1) => panjang vektor a = |a| = √(1^2 + 1^2) = √(1 + 1) = √2
    Sudut yang dibentuk a dan sumbu x positif :
    Tan ¢ = y/x = 1/1 = 1 = Tan 45°
    ¢ = 45° = π/4

    3) a = (-3 , -2), b = (-5 , 4), c = (9 , -16)
    A. c = 3a - 2b = (-9, -6) - (-10, 8) = (1, -14) ..... salah
    B. c = -3a + 2b = (9, 6) + (-10, 8) = (-1, 14) ..... salah
    C. c = 2a - 3b = (-6, -4) - (-15, 12) = (9, -16) .... BENAR

    4) PQ = 1/7 PR => PR = 7 PQ
    SR = 1/2 QR

    QR = QP + PR = -PQ + 7PQ = 6PQ

    PS = PR + RS
    = PR - SR
    = 7PQ - 1/2 QR
    = 7PQ - 1/2 (6PQ)
    = 7PQ - 3PQ
    = 4PQ

    Jadi PR : PS = 7 PQ : 4 PQ = 7 : 4

    5) buat gambar segienam ABCDEF
    CD = CB + BA + AD
    = CB + BA + 2(BC)
    = b - c + a - b + 2(c - b)
    = -c + a + 2c - 2b
    = a - 2b + c