diketahui fungsi f(x)= a x + b. jika f(2) = 11 dan f(4)= 17. maka rumus fungsi f(x) adalah

f(x) = ax + b
f(2) = 11
f(4) = 17

eliminasi
f(2) = a(2) + b = 11
f(4) = a(4) + b = 17
------------------------ -
-2a = -5
a = 5/2
b = 2(5/2) + b = 11
= 5 + b = 11
= b = 6
rumus fungsi f(x) = 5/2x + 6

maaf jika saya salah :)