tentukan luas nya ya plizz

beri O sebagai potongan di tengah
AB = 24, diagonal potongnya = 1/2 x 24 = 12 cm = DO = BO

-> theorema pitagoras: 12,13, 5.
AO = 5cm

OC= [tex] \sqrt{ 20^{2}- 12^{2} } = \sqrt{400-144} = \sqrt{256} = 16 [/tex] cm

-> Luas = d1 x d2 x 1/2
= 24 x (16+5) x 1/2
= 12 x 21
= 252 cm2.