Matematika

Pertanyaan

nilai lim x-7 2x^2-8x-42/x^2-10x+21

1 Jawaban

  • (2x² - 8x - 42)/(x² - 10x + 21)
    = (2(x² - 4x - 21))/(x² - 10x + 21)
    = (2(x - 7)(x + 3))/((x - 7)(x - 3))
    = (2(x + 3))/(x - 3)
    = (2x + 6)/(x - 3)
    = (2(7) + 6)/(7 - 3)
    = (14 + 6)/4
    = 20/4
    = 5

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