sebanyak 300 ml larutan HCL 0,1 di reaksikan dengan 200 ml KOH 0,2 m . berapa pH masing masing larutan sebelum di campur dan berapa pH campuran?

pH HCl = -log[H+] = -log[10^-1] = 1
pOH KOH = -log[OH-] = -log[2.10^-1] = 1 - log 2; pH KOH = 13 + log 2

HCl + KOH -> KCl +H2O
m 30 40 -
r 30 30 30
s 0 10 30

Tersisa 10 mmol KOH, maka Molaritas KOH = mol/volume total = 10/500 = 2 x 10^-2 M
OH- = 2 x 10^-2
pOH = -log[2x10^-2]
pOH = 2 - log 2
pH = 12 + log2